CS501 – Advance Computer Architecture
In CS501 Advance Computer Architecture we have you covered with Digitized Past Papers From Fall of Mid Term and Final Term.
NOTE: Tab/Click on Preparation Tab to take the MCQ’s Tests.
POSTED DATE:30-01-2019
Solution Of Question No.01:
In one second transfer rate = 9600 bytes
Equelant to 9600/4 = 2400 DMA cycles as 4 bytes are transferred in every cycle
Earlier in 1 second 2000000 instructions were executed.
Now in 1 second (2000000-2400) = 1997600 instructions are executed
Solution Of Question No.02:
8086 Interrupts:
| Category | Sub_Category |
| Non-Maskable | Invalid opcode |
| Mouse | File Deletion |
| Breakpoint | Arithmetic overflows |
| Stack Overflow | Trap |
| Divide by zero | |
| Mode Switching |
CS501– Practice Quiz 1
CS501– Practice Quiz 2
CS501– Practice Quiz 3
1. Define PROM? (2 Marks)
Answer:- (Page 356)
The PROM stands for Programmable Read only Memory. It is also nonvolatile and may be written into only
once. For PROM, the writing process is performed electrically in the field. PROMs provide flexibility and
convenience.
2. How we refer the register to the RTL? Give an example? (2 Marks)
Answer:- (Page 66)
Specifying Registers
The format used to specify registers is
Register Name
For example, IR means bits numbered 31 to 0 of a 32-bit register named “IR”
(Instruction Register).
3. What is the use of modem? (2 Marks)
Answer:- (Page 391)
To interconnect different computers by using twisted pair copper wire, an interface is used which is called
modem. Modem stands for modulation/demodulation. Modems are very useful to utilize the telephone network
(i.e. 4 KHz bandwidth) for data and voice transmission.
4. What is the advantage of RAID level 0? (2 Marks)
Answer:- (Page 330)
• The user and system data are distributed across all the disks in the array.
• Notable advantage over the use of a single large disk.
Q1-Write two lines on connection oriented communication? 2
Answer:- (Page 394)
In this method, same path is always taken for the transfer of messages.
It reserves the bandwidth until the transfer is complete. So no other server could use that path until it becomes
free.
Q2-What is the advantage of direct cache memory? 2
Answer:- (Page 361)
Advantage is Simplicity.
4
Q3-Write the drawbacks of DMA? 2
Answer:- (Page 315)
The disadvantage however, would be that an additional DMA controller would be required, that could make
the system a bit more complex and expensive. Generally, the DMA requests have priority over all other bus
activities including interrupts. No interrupts may be recognized during a DMA cycle.
Q4-What is the difference between selection channel and multiple channels? 3
Answer:- (Page 320)
Selector Channel
It is the DMA controller that can do block transfers for several devices but only one at a time.
Multiplexer Channel
It is the DMA controller that can do block transfers for several devices at once.
Q5-What is the advantage of linker in assembly language program? 3
Answer:- (Page 26)
When developing large programs, different people working at the same time can develop separate modules of functionality. These modules can then be „linked‟ to form a single module that can be loaded and executed. The modularity of programs, that the linking step in assembly language makes possible, provides the same convenience as it does in higher-level languages; namely abstraction and separation of concerns. Once the functionality of a module has been verified for correctness, it can be re-used in any number of other modules.
The programmer can focus on other parts of the program. This is the so-called “modular” approach, or the “topdown” approach.